If a and b are natural numbers such that a > b, then the equation x + a = b is not solvable in N, the set of natural numbers. This means that there is no natural number satisfying the equation x + a = b. so, the set of natural numbers is extended to form the set I of integers in which every equation of the form x + a = b, for a and b being natural numbers is solvable. However, the equations of the form x a = b, where a ≠ 0 and a and b being integers are not solvable for I also. Hence, the set I of integers is extended to obtain the set Q of all rational numbers in which every equation of the form x a = b, where a ≠ 0 and a and b being integers is solvable. But, the equations of the form x 2 = 2, x 2 = 3 etc. are not solvable in Q because there is no rational number whose square is 2. Such numbers are known as irrational numbers. The set Q of all rational numbers is extended to obtain the set of R of real numbers that include both rational and irrational numbers. However, the equations of the form x 2 + 1 = 0, x 2 + 4 = 0, etc. are not solvable in R which means that there is no real number whose square is a negative real number. Euler was the first mathematician to introduce the symbol i ( iota ) for the square of – 1, i.e. a solution of x 2 + 1 = 0 with the property i 2 = – 1. He also called this symbol as the imaginary unit. This gave the concept of complex numbers Let us learn more about them.
The complex conjugate of a complex number, z, is its mirror image with respect to the horizontal axis ( or x – axis ). In other words, a complex conjugate of a complex number is another complex number whose real part is the same as the original complex number and the magnitude of the imaginary part is the same with the opposite sign. This is similar to the definition of a conjugate we learn in mathematics in general. A conjugate in Mathematics is formed by changing the sign of one of the terms in a binomial. For example, if the binomial number is a + b, the conjugate of this number will be formed by changing the sign of either of the terms. If we change the sign of b, the conjugate formed will be a – b. Therefore, in mathematics, a + b and a – b are both conjugates of each other.
Let z = a + i b be a complex number. Then the conjugate of z is defined by $\overline$ and is equal to a – i b.
Thus, if z = a + i b ⇒ $\overline$ = a – i b
Therefore, it follows from the definition that the conjugate of a complex number is obtained by replacing i by – i .
Let us understand it through an example.
Suppose we have a complex number z = 3 + 4 i. What would be the conjugate of this complex number?
The conjugate of the complex number z = 3 + 4 I would be z = 3 – 4 i
The following are the properties of the conjugate of a complex number –
If z 1, z 2, and z 3 are three complex numbers and let z = a + i b, z 1 = a 1 + i b 1 and z 2 = a 2 + i b 2 Then,
Let us recall what we mean by an argand diagram of a complex number. A complex number z = x + i y can be represented by a point ( x, y ) on the plane which is known as the Argand plane. To represent z = x + i y in geometric form, we take mutually perpendicular straight lines. Now we will plot a point whose x and y coordinates are represented by the real and the imaginary parts of z. This point P ( x, y ) represents the complex number z = x + i y. Below is the geometric representation of the point P ( x, y ) on the complex plane.
Some important points to remember here are –
Let us now discuss the Argument or Amplitude of a Complex number for different signs of real and imaginary parts. There can be four different conditions depending upon the signs of real and imaginary parts. These four conditions are –
Let us discuss these one by one
Since x and y are both positive, therefore, the point P ( x, y ) representing z = x + i y in the Argand plane lies in the first quadrant. Let be the argument of z and let θ be the acute angle satisfying tan = | y / x | . Below is the geometrical representation of this case –
Since x is less than zero, which means it is negative and y is positive, therefore, the point P ( x, y ) representing z = x + i y in the Argand plane lies in the second quadrant. Let be the argument of z and let be the acute angle satisfying tan = | y / x | . Below is the geometrical representation of this case –
Since x and y are both negative, therefore, the point P ( x, y ) representing z = x + i y in the Argand plane lies in the third quadrant. Let be the argument of z and let be the acute angle satisfying tan = | y / x | . Below is the geometrical representation of this case –
Since y is less than zero, which means it is negative and x is positive, therefore, the point P ( x, y ) representing z = x + i y in the Argand plane lies in the fourth quadrant. Let be the argument of z and let be the acute angle satisfying tan = | y / x | . Below is the geometrical representation of this case –
From the above, we can define an algorithm for finding the argument of a complex number using the complex plane.
Now, the argand diagram of the conjugate of a complex number will be –
The length of line joining the number is its absolute value also known as modulus and the angle, this line makes with positive side of real axis or x – axis is known as argument of the number.
Let us consider two complex numbers, say, z1 = ( a + i b ) and z2 = ( c + i d ). Let us how we can multiply these two complex numbers.
Since we need to multiply z1 and z2, we will have,
z1 x z2 = ( a + i b ) ( c + i d ) . . . . . . . . . . . . . . . . . . . . . . . . . ( 1 )
⇒ z1 x z2 = a c + i ( a d ) + i ( b c ) + i 2 ( b d )
We know that i 2 = – 1 , therefore, substituting the value of i 2 in the above equation, we will have,
z1 x z2 = a c + i ( a d ) + i ( b c ) + ( – 1 ) ( b d )
Now, we will combine the real numbers with the imaginary numbers, we will get,
z1 x z2 = ( a c – b d ) + i ( a d + b c ) . . . . . . . . . . . . . . . . ( 2 )
So, we can say that for any two complex numbers, z1 = ( a + i b ) and z2 = ( c + i d ), z1 x z2 = ( a c – b d ) + i ( a d + b c )
Now, when a complex number is multiplied by its complex conjugate, the product is a real number whose value is equal to the square of the magnitude of the complex number.
Now, (a + i b )( a – i b ) = a 2 – ( i b ) 2 = a 2 – i 2 b 2 = a 2 + b 2
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