Hash table runtime complexity (insert, search and delete)

Why do I keep seeing different runtime complexities for these functions on a hash table? On wiki, search and delete are O(n) (I thought the point of hash tables was to have constant lookup so what's the point if search is O(n)). In some course notes from a while ago, I see a wide range of complexities depending on certain details including one with all O(1). Why would any other implementation be used if I can get all O(1)? If I'm using standard hash tables in a language like C++ or Java, what can I expect the time complexity to be?

user3133925 asked Feb 9, 2012 at 16:04 user1136342 user1136342 4,901 11 11 gold badges 31 31 silver badges 40 40 bronze badges

a perfect has is O(1) lookup, but for that you have to know what the data will be when you design the table.

Commented Feb 9, 2012 at 16:15

O(n) is worst case, O(1) is average case. In the worst case, you could be inserting N elements all of which hash to the same bucket. Then, for this data set, deletion and search will also be O(n).

Commented Feb 9, 2012 at 16:25 Commented May 24, 2015 at 13:32

5 Answers 5

Hash tables are O(1) average and amortized case complexity, however it suffers from O(n) worst case time complexity. [And I think this is where your confusion is]

Hash tables suffer from O(n) worst time complexity due to two reasons:

  1. If too many elements were hashed into the same key: looking inside this key may take O(n) time.
  2. Once a hash table has passed its load balance - it has to rehash [create a new bigger table, and re-insert each element to the table].

However, it is said to be O(1) average and amortized case because:

  1. It is very rare that many items will be hashed to the same key [if you chose a good hash function and you don't have too big load balance.
  2. The rehash operation, which is O(n) , can at most happen after n/2 ops, which are all assumed O(1) : Thus when you sum the average time per op, you get : (n*O(1) + O(n)) / n) = O(1)

Note because of the rehashing issue - a realtime applications and applications that need low latency - should not use a hash table as their data structure.

EDIT: Annother issue with hash tables: cache
Another issue where you might see a performance loss in large hash tables is due to cache performance. Hash Tables suffer from bad cache performance, and thus for large collection - the access time might take longer, since you need to reload the relevant part of the table from the memory back into the cache.

11k 6 6 gold badges 64 64 silver badges 86 86 bronze badges answered Feb 9, 2012 at 16:17 178k 27 27 gold badges 242 242 silver badges 341 341 bronze badges

Thanks- I think I understand. So if I was asked during an exam or an interview to come up with a data structure that performs lookup in O(1), do you know if including a hash table would be fine?

Commented Feb 9, 2012 at 16:24

@user1136342: It depends if you need worst case or average case. For average case, hash tables are O(1) . If you need worst case - hash table will not be enough.

Commented Feb 9, 2012 at 16:29

Wikipedia says the worst case can be reduced from O(n) to O(log n) by using a more complex data structure within each bucket. (I guess this could be considered overkill if the hashtable is already using a good cryptographic hash, which would prevent collisions even from an attacker.)

Commented May 5, 2020 at 12:24

@joeytwiddle a sorted array as a secondary data structure is not hard to do and then you can indeed guarantee O(log(n)) worst case for lookups. There are other hash tables that can guarantee O(log(n)) worst case for lookups like hash ordering and by using a perfect hash table of size n² as a secondary data structure you can even guarantee O(1) worst case lookups.

Commented Jul 2, 2020 at 11:09

@codexplorer No. Theta/big O/. are all about the bound - and unrelated to how you analyze your algorithm. I tried to explain about it a bit in this thread.

Commented Aug 16, 2021 at 6:01

Ideally, a hashtable is O(1) . The problem is if two keys are not equal, however they result in the same hash.

For example, imagine the strings "it was the best of times it was the worst of times" and "Green Eggs and Ham" both resulted in a hash value of 123 .

When the first string is inserted, it's put in bucket 123. When the second string is inserted, it would see that a value already exists for bucket 123 . It would then compare the new value to the existing value, and see they are not equal. In this case, an array or linked list is created for that key. At this point, retrieving this value becomes O(n) as the hashtable needs to iterate through each value in that bucket to find the desired one.

For this reason, when using a hash table, it's important to use a key with a really good hash function that's both fast and doesn't often result in duplicate values for different objects.